I have updated the notes to go as far as next Wednesday, Lecture 9. By the way, if you are printing these notes, you can choose the format you most prefer. I use Acrobat to print with "Fit" which gives me a large typeface on A4. But "Actual size" (to give you wide margins) or "multiple pages" 2 per sheet can look nice also.
I have made some small changes to Example 5.2 in the notes for Lecture 5, and one important correction to a typo in the formula for the Poisson distribution. By the way, I mentioned horse kicks. I was imperfectly recalling that a famous example of data that is Poisson distributed is due to von Bortkiewicz (1898), who studied the numbers of Prussian cavalryman being killed by the kick of a horse in each of 20 years. This is an example with n (number of cavalryman) large, and p (chance a particular cavalryman being killed) small. You can read more about this famous example here.
You might compare the answer to Examples Sheet 1 #10 to a Bonferroni inequality working in the reverse direction, ≥.
We saw by examples today that it is possible to have three events A1,A2,A3 such that every pair of events is independent, but the three events are not mutually independent. Here is another example. Suppose the sample sample consists of 4 equally likely outcomes {w1,w2,w3,w4}. Let
A1={w1,w2},
A2={w1,w3},
A3={w1,w4}.
Then P(Ai∩Aj)=P(Ai)P(Aj)=1/4, but 1/4=P(A1∩A2∩A3)≠P(A1)P(A2)P(A3)=1/8.
I mentioned in the lecture that we might generalize this to a puzzle. Can you find four events A1,A2,A3,A4 such that every subset of either two or three events is a set of mutually independent events, but the four events are not mutually independent?
At the end of the lecture a student told me this nice answer. Let Ai be the probability the ith dice roll is odd, i=1,2,3 and A4 be the event the sum of the three rolls is even. That works! And it looks like we could generalize this example to give A1,…,Ak+1 such that every k or fewer events are independent, but the k+1 events are not independent.
You can find another answer at the end of this page, but I think the above is nicer.
I have made some small changes to Example 5.2 in the notes for Lecture 5, and one important correction to a typo in the formula for the Poisson distribution. By the way, I mentioned horse kicks. I was imperfectly recalling that a famous example of data that is Poisson distributed is due to von Bortkiewicz (1898), who studied the numbers of Prussian cavalryman being killed by the kick of a horse in each of 20 years. This is an example with n (number of cavalryman) large, and p (chance a particular cavalryman being killed) small. You can read more about this famous example here.
You might compare the answer to Examples Sheet 1 #10 to a Bonferroni inequality working in the reverse direction, ≥.
We saw by examples today that it is possible to have three events A1,A2,A3 such that every pair of events is independent, but the three events are not mutually independent. Here is another example. Suppose the sample sample consists of 4 equally likely outcomes {w1,w2,w3,w4}. Let
A1={w1,w2},
A2={w1,w3},
A3={w1,w4}.
Then P(Ai∩Aj)=P(Ai)P(Aj)=1/4, but 1/4=P(A1∩A2∩A3)≠P(A1)P(A2)P(A3)=1/8.
I mentioned in the lecture that we might generalize this to a puzzle. Can you find four events A1,A2,A3,A4 such that every subset of either two or three events is a set of mutually independent events, but the four events are not mutually independent?
At the end of the lecture a student told me this nice answer. Let Ai be the probability the ith dice roll is odd, i=1,2,3 and A4 be the event the sum of the three rolls is even. That works! And it looks like we could generalize this example to give A1,…,Ak+1 such that every k or fewer events are independent, but the k+1 events are not independent.
You can find another answer at the end of this page, but I think the above is nicer.